What is the integral from pi to 2pi of sin(θ) ?

The integral from pi to 2pi of sin(θ) is -2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from pi to 2pi of sin(θ)

\int_{π}^{2 π} sin (θ) d θ

- 2

Solution steps

\int_{π}^{2 π} sin (θ) d θ

Use the common integral:

\int sin (θ) d θ = - cos (θ)

= [- cos (θ)]_{π}^{2 π}

Compute the boundaries:

- 2

= - 2

\int_{0}^{3} sin (\frac{π}{6} x) d x

\int_{1}^{7} \frac{4 ( ln ( x ) ) ^{3}}{x} d x

\int_{0}^{3} \frac{x}{x ^{2} - 7 x + 12} d x

\int_{2}^{4} 8 x^{2} d x

\int_{- \frac{π}{2}}^{π} 2 cos (x) d x

What is the integral from pi to 2pi of sin(θ) ?
The integral from pi to 2pi of sin(θ) is -2