What is the integral from 1 to 3 of x/4 ?

The integral from 1 to 3 of x/4 is 1

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integral from 1 to 3 of x/4

\int_{1}^{3} \frac{x}{4} d x

1

Solution steps

\int_{1}^{3} \frac{x}{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{1}^{3} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{1}^{3}

= \frac{1}{4} [\frac{x ^{2}}{2}]_{1}^{3}

Compute the boundaries:

4

= \frac{1}{4} \cdot 4

Simplify

= 1

\int_{0}^{1} x 4 x^{2} + 2 d x

\int_{1}^{0} e^{- x} d x

\int_{\frac{1}{2}}^{1} (x^{- 3} - 4) d x

\int_{- 4}^{4} x^{2} 64 - x^{3} d x

\int_{0}^{0.5} e^{x - 1} d x