What is the integral from 0 to 1 of sqrt(1x+4) ?

The integral from 0 to 1 of sqrt(1x+4) is (10sqrt(5)-16)/3

Popular >

integral from 0 to 1 of sqrt(1x+4)

\int_{0}^{1} 1 x + 4 d x

\frac{10 5 - 16}{3}

Solution steps

\int_{0}^{1} 1 \cdot x + 4 d x

Simplify

= \int_{0}^{1} x + 4 d x

Apply u-substitution

: \int_{4}^{5} u d u

= \int_{4}^{5} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{5}

= [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{5}

Compute the boundaries:

\frac{10 5}{3} - \frac{16}{3}

= \frac{10 5}{3} - \frac{16}{3}

Simplify

= \frac{10 5 - 16}{3}

\int_{1}^{2} \frac{x ^{3} + 2}{x ^{2}} d x

\int_{2}^{5} (2 x - 3)^{4} d x

\int_{1}^{3} (\frac{1}{x} + \frac{1}{x ^{2}}) d x

\int_{0}^{2} (6 x - 6) (8 x^{2} + 4) d x

\int_{- \infty}^{e} 24 e^{- x} d x

What is the integral from 0 to 1 of sqrt(1x+4) ?
The integral from 0 to 1 of sqrt(1x+4) is (10sqrt(5)-16)/3