What is the integral from 0 to 1 of 1/t ?

The integral from 0 to 1 of 1/t is diverges

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integral from 0 to 1 of 1/t

\int_{0}^{1} \frac{1}{t} d t

diverges

Solution steps

\int_{0}^{1} \frac{1}{t} d t

Use the common integral:

\int \frac{1}{t} d t = ln (∣ t ∣)

= [ln ∣ t ∣]_{0}^{1}

Compute the boundaries:

diverges

= diverges

\int_{- \infty}^{1} 0 d x

\int_{0}^{2} \frac{2 t}{1 + t ^{2}} d t

\int_{- 3}^{4} - x^{2} + x + 12 d x

\int_{- 2}^{3} (3 x^{2} - 4 x) d x

\int_{- 2}^{3} 6 d x

What is the integral from 0 to 1 of 1/t ?
The integral from 0 to 1 of 1/t is diverges