What is the integral from 1 to pi/2 of sin(x) ?

The integral from 1 to pi/2 of sin(x) is cos(1)

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integral from 1 to pi/2 of sin(x)

\int_{1}^{\frac{π}{2}} sin (x) d x

cos (1)

Solution steps

\int_{1}^{\frac{π}{2}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{1}^{\frac{π}{2}}

Compute the boundaries:

cos (1)

= cos (1)

\int_{1}^{3} (x^{2} + 5) d x

\int_{1}^{2} f (2 x) d x

\int_{0}^{4} x (x + 1) d x

\int_{\frac{π}{6}}^{\frac{π}{3}} \frac{1}{sin ( x )} d x

\int_{3}^{4} x - 3 d x

What is the integral from 1 to pi/2 of sin(x) ?
The integral from 1 to pi/2 of sin(x) is cos(1)