What is the integral from 4 to 1 of x^2 ?

The integral from 4 to 1 of x^2 is -21

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integral from 4 to 1 of x^2

\int_{4}^{1} x^{2} d x

- 21

Solution steps

\int_{4}^{1} x^{2} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{1}^{4} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{4}

= - [\frac{x ^{3}}{3}]_{1}^{4}

Compute the boundaries:

21

= - 21

\int_{0}^{l n (2)} e^{- 2 y} d y

\int_{- 1}^{3} 6 x^{2} - x^{3} - 8 x d x

\int_{0}^{1} \frac{x}{1 - x} d x

\int_{0}^{2} x^{3} - 4 x + 3 d x

\int_{2}^{3} \frac{2}{x ^{3}} d x

What is the integral from 4 to 1 of x^2 ?
The integral from 4 to 1 of x^2 is -21