What is area y=-x^2+16,y=(-1)/4 x-1,y=x-6.6 ?

The answer to area y=-x^2+16,y=(-1)/4 x-1,y=x-6.6 is No Solution

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area y=-x^2+16,y=(-1)/4 x-1,y=x-6.6

area

y = - x^{2} + 16, y = \frac{- 1}{4} x - 1, y = x - 6.6

No Solution

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

- x^{2} + 16 = \frac{- 1}{4} x - 1 : x = - 4, x = \frac{17}{4}

- x^{2} + 16 = x - 6.6 : x = - \frac{5 + 2285}{10}, x = \frac{2285 - 5}{10}

\frac{- 1}{4} x - 1 = x - 6.6 : x = 4.48

Curves not bounded

= No Solution

y = \frac{7 x ^{2} + 5}{x ^{2} + 9}

f (x) = x e^{x}

\frac{d x}{d t} = 4000 - \frac{x}{50 + t}

\frac{x ^{2} + 1}{x ^{2} + 1 + x}

What is area y=-x^2+16,y=(-1)/4 x-1,y=x-6.6 ?
The answer to area y=-x^2+16,y=(-1)/4 x-1,y=x-6.6 is No Solution