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Popular >

integral from 6 to 9 of (x^2+x)

Solution

\int_{6}^{9} (x^{2} + x) d x

Solution

\frac{387}{2}

+1

Solution steps

\int_{6}^{9} x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{6}^{9} x^{2} d x + \int_{6}^{9} x d x

\int_{6}^{9} x^{2} d x = 171

\int_{6}^{9} x d x = \frac{45}{2}

= 171 + \frac{45}{2}

Simplify

171 + \frac{45}{2} : \frac{387}{2}

= \frac{387}{2}

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\int_{0}^{1} x^{3} arctan (x) d x

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\int_{0}^{2} x^{3} - 2 x d x

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\int_{1}^{3} \frac{2 x - 1}{( x + 1 ) ^{2}} d x

integral from 2 to 4 of (x/2-(2x^2)/3)

\int_{2}^{4} (\frac{x}{2} - \frac{2 x ^{2}}{3}) d x

integral from-1 to 1 of x^{-1}

\int_{- 1}^{1} x^{- 1} d x

Frequently Asked Questions (FAQ)

What is the integral from 6 to 9 of (x^2+x) ?
The integral from 6 to 9 of (x^2+x) is 387/2