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Popular >

integral from 0 to 1 of (1-y^2)

Solution

\int_{0}^{1} (1 - y^{2}) d y

Solution

\frac{2}{3}

+1

Solution steps

\int_{0}^{1} 1 - y^{2} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 1 d y - \int_{0}^{1} y^{2} d y

\int_{0}^{1} 1 d y = 1

\int_{0}^{1} y^{2} d y = \frac{1}{3}

= 1 - \frac{1}{3}

Simplify

1 - \frac{1}{3} : \frac{2}{3}

= \frac{2}{3}

Popular Examples

integral from 0 to 4 of 8x^2

\int_{0}^{4} 8 x^{2} d x

integral from 1 to 7 of (t^2-2t-24)

\int_{1}^{7} (t^{2} - 2 t - 24) d t

integral from 0 to 4 of x^2+2x-3

\int_{0}^{4} x^{2} + 2 x - 3 d x

integral from-8 to 4 of (-x^2-3x)

\int_{- 8}^{4} (- x^{2} - 3 x) d x

integral from 1 to 2 of 1/(5x)

\int_{1}^{2} \frac{1}{5 x} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (1-y^2) ?
The integral from 0 to 1 of (1-y^2) is 2/3