What is the integral from-1 to 1 of 3x^4 ?

The integral from-1 to 1 of 3x^4 is 6/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of 3x^4

\int_{- 1}^{1} 3 x^{4} d x

\frac{6}{5}

Solution steps

\int_{- 1}^{1} 3 x^{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{- 1}^{1} x^{4} d x

Apply the Power Rule

: [\frac{x ^{5}}{5}]_{- 1}^{1}

= 3 [\frac{x ^{5}}{5}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{5}

= 3 \cdot \frac{2}{5}

Simplify

= \frac{6}{5}

\int_{0}^{\frac{π}{2}} 3 sin (x) cos (x) d x

\int_{1}^{4} 2 x^{2} + 3 x - 1 d x

\int_{1}^{2} 2 x (x - 1) d x

\int_{0}^{8} 2 b x^{- \frac{1}{3}} d x

\int_{0}^{\infty} e^{- λ x} d x

What is the integral from-1 to 1 of 3x^4 ?
The integral from-1 to 1 of 3x^4 is 6/5