What is the integral from 0 to 4 of 8x^3 ?

The integral from 0 to 4 of 8x^3 is 512

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of 8x^3

\int_{0}^{4} 8 x^{3} d x

512

Solution steps

\int_{0}^{4} 8 x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{0}^{4} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{4}

= 8 [\frac{x ^{4}}{4}]_{0}^{4}

Compute the boundaries:

64

= 8 \cdot 64

Simplify

= 512

\int_{x}^{x^{2} + 1} 2 x y d y

\int_{1}^{2} \frac{e ^{\frac{2}{x}}}{x ^{2}} d x

\int_{9}^{27} 1

\int_{- 4}^{4} (5 - ∣ x ∣) d x

\int_{0}^{t} 1000 x + 250 d x

What is the integral from 0 to 4 of 8x^3 ?
The integral from 0 to 4 of 8x^3 is 512