en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to 2 of (x^2+x)

Solution

\int_{- 2}^{2} (x^{2} + x) d x

Solution

\frac{16}{3}

+1

Solution steps

\int_{- 2}^{2} x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{2} x^{2} d x + \int_{- 2}^{2} x d x

\int_{- 2}^{2} x^{2} d x = \frac{16}{3}

\int_{- 2}^{2} x d x = 0

= \frac{16}{3} + 0

Simplify

= \frac{16}{3}

Popular Examples

integral from-1 to 2 of (x^2+x-4)

\int_{- 1}^{2} (x^{2} + x - 4) d x

integral from 7 to 25 of x^2(x-7)/(162)

\int_{7}^{25} x^{2} \frac{x - 7}{162} d x

integral from 1 to e of (1+x^2)ln(x)

\int_{1}^{e} (1 + x^{2}) ln (x) d x

integral from 1 to 3 of 1-sqrt(4x-x^2-3)

\int_{1}^{3} 1 - 4 x - x^{2} - 3 d x

integral from 0 to 1 of 12xe^x

\int_{0}^{1} 12 x e^{x} d x

Frequently Asked Questions (FAQ)

What is the integral from-2 to 2 of (x^2+x) ?
The integral from-2 to 2 of (x^2+x) is 16/3