What is the integral from 1 to 3 of 1/((x+7)^2) ?

The integral from 1 to 3 of 1/((x+7)^2) is 1/40

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 3 of 1/((x+7)^2)

\int_{1}^{3} \frac{1}{( x + 7 ) ^{2}} d x

\frac{1}{40}

Solution steps

\int_{1}^{3} \frac{1}{( x + 7 ) ^{2}} d x

Apply u-substitution

: \int_{8}^{10} \frac{1}{u ^{2}} d u

= \int_{8}^{10} \frac{1}{u ^{2}} d u

Apply the Power Rule

: [- \frac{1}{u}]_{8}^{10}

= [- \frac{1}{u}]_{8}^{10}

Compute the boundaries:

\frac{1}{40}

= \frac{1}{40}

\int_{4}^{14} (4 - x) (x - 14) d x

\int_{0}^{π} sin (\frac{x}{2}) cos (n x) d x

\int_{- 2}^{4} 3 x - 9 d x

\int_{0}^{2} x^{3} 1 + x^{4} d x

\int_{- \frac{π}{2}}^{\frac{π}{2}} cos^{2} (θ) d θ

What is the integral from 1 to 3 of 1/((x+7)^2) ?
The integral from 1 to 3 of 1/((x+7)^2) is 1/40