What is the integral from 2 to 8 of (68+47) ?

The integral from 2 to 8 of (68+47) is 690

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to 8 of (68+47)

\int_{2}^{8} (68 + 47) d x

690

Solution steps

\int_{2}^{8} 68 + 47 d x

Integral of a constant:

\int a d x = a x

= [(68 + 47) x]_{2}^{8}

Simplify

= [115 x]_{2}^{8}

Compute the boundaries:

690

= 690

\int_{0}^{3} \frac{x}{x ^{2} + 9} d x

\int_{- 5}^{0} x 25 - x^{2} d x

\int_{0}^{x^{2}} sin (θ^{2}) d θ

\int_{\infty}^{0} \frac{1}{3 - 4 x} d x

\int_{0}^{2} 2 x d x

What is the integral from 2 to 8 of (68+47) ?
The integral from 2 to 8 of (68+47) is 690