What is (\partial)/(\partial x)(-xyz^2+27) ?

The answer to (\partial)/(\partial x)(-xyz^2+27) is -yz^2

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(\partial)/(\partial x)(-xyz^2+27)

\frac{\partial}{\partial x} (- x y z^{2} + 27)

- y z^{2}

Solution steps

\frac{\partial}{\partial x} (- x y z^{2} + 27)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (x y z^{2}) + \frac{\partial}{\partial x} (27)

\frac{\partial}{\partial x} (x y z^{2}) = y z^{2}

\frac{\partial}{\partial x} (27) = 0

= - y z^{2} + 0

Simplify

= - y z^{2}

\frac{d}{d x} (ln (x^{2} - 9 x + 1))

n = 0 \sum \infty \frac{n ^{10} \cdot 1 0 ^{n}}{n !}

\int \frac{1}{x ^{2} - 6 x + 10} d x

\int x^{2} - 2 x - 15 d x

\frac{\partial}{\partial y} (\frac{y}{y + 4 x})

What is (\partial)/(\partial x)(-xyz^2+27) ?
The answer to (\partial)/(\partial x)(-xyz^2+27) is -yz^2