What is the integral from 1 to 9 of x^{1/2} ?

The integral from 1 to 9 of x^{1/2} is 52/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 9 of x^{1/2}

\int_{1}^{9} x^{\frac{1}{2}} d x

\frac{52}{3}

Solution steps

\int_{1}^{9} x^{\frac{1}{2}} d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{1}^{9}

= [\frac{2}{3} x^{\frac{3}{2}}]_{1}^{9}

Compute the boundaries:

\frac{52}{3}

= \frac{52}{3}

\int_{1}^{2.2} x^{3} e^{x + 1} d x

\int_{0}^{1} \frac{4 x}{1 + x ^{2}} d x

\int_{2}^{3} \frac{3 x}{1 + x ^{2}} d x

\int_{12}^{37} x x^{2} - 144 d x

\int_{1}^{3} \frac{1}{4 x} d x

What is the integral from 1 to 9 of x^{1/2} ?
The integral from 1 to 9 of x^{1/2} is 52/3