What is the integral from 1 to 3 of x^{3/4} ?

The integral from 1 to 3 of x^{3/4} is (12*3^{3/4}-4)/7

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integral from 1 to 3 of x^{3/4}

\int_{1}^{3} x^{\frac{3}{4}} d x

\frac{12 \cdot 3 ^{\frac{3}{4}} - 4}{7}

Solution steps

\int_{1}^{3} x^{\frac{3}{4}} d x

Apply the Power Rule

: [\frac{4}{7} x^{\frac{7}{4}}]_{1}^{3}

= [\frac{4}{7} x^{\frac{7}{4}}]_{1}^{3}

Compute the boundaries:

\frac{12 \cdot 3 ^{\frac{3}{4}}}{7} - \frac{4}{7}

= \frac{12 \cdot 3 ^{\frac{3}{4}}}{7} - \frac{4}{7}

Simplify

= \frac{12 \cdot 3 ^{\frac{3}{4}} - 4}{7}

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What is the integral from 1 to 3 of x^{3/4} ?
The integral from 1 to 3 of x^{3/4} is (12*3^{3/4}-4)/7