What is the integral from 0 to 2 of z^2 ?

The integral from 0 to 2 of z^2 is 8/3

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integral from 0 to 2 of z^2

\int_{0}^{2} z^{2} d z

\frac{8}{3}

Solution steps

\int_{0}^{2} z^{2} d z

Apply the Power Rule

: [\frac{z ^{3}}{3}]_{0}^{2}

= [\frac{z ^{3}}{3}]_{0}^{2}

Compute the boundaries:

\frac{8}{3}

= \frac{8}{3}

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What is the integral from 0 to 2 of z^2 ?
The integral from 0 to 2 of z^2 is 8/3