What is the integral from 2pi to 4pi of sin(x) ?

The integral from 2pi to 4pi of sin(x) is 0

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integral from 2pi to 4pi of sin(x)

\int_{2 π}^{4 π} sin (x) d x

0

Solution steps

\int_{2 π}^{4 π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{2 π}^{4 π}

Compute the boundaries:

0

= 0

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\int_{5}^{6} x^{2} - 8 x + 15 d x

\int_{0}^{t} t e^{- k t} d t

\int_{0}^{x} \frac{x y}{1 + x ^{4}} d y

What is the integral from 2pi to 4pi of sin(x) ?
The integral from 2pi to 4pi of sin(x) is 0