What is the integral from 1 to 2 of ln(y) ?

The integral from 1 to 2 of ln(y) is 2ln(2)-1

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integral from 1 to 2 of ln(y)

\int_{1}^{2} ln (y) d y

2 ln (2) - 1

Solution steps

\int_{1}^{2} ln (y) d y

Apply Integration By Parts

: [y ln (y) - \int 1 d y]_{1}^{2}

= [y ln (y) - \int 1 d y]_{1}^{2}

\int 1 d y = y

= [y ln (y) - y]_{1}^{2}

Compute the boundaries:

2 ln (2) - 1

= 2 ln (2) - 1

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What is the integral from 1 to 2 of ln(y) ?
The integral from 1 to 2 of ln(y) is 2ln(2)-1