What is the integral from 0 to 1 of \sqrt[4]{x}+1 ?

The integral from 0 to 1 of \sqrt[4]{x}+1 is 9/5

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integral from 0 to 1 of \sqrt[4]{x}+1

\frac{9}{5}

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int_{0}^{1} 1 d x = 1

= \frac{4}{5} + 1

Simplify

\frac{4}{5} + 1 : \frac{9}{5}

= \frac{9}{5}

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What is the integral from 0 to 1 of \sqrt[4]{x}+1 ?
The integral from 0 to 1 of \sqrt[4]{x}+1 is 9/5