en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of 1+x^2

Solution

\int_{- 1}^{1} 1 + x^{2} d x

Solution

\frac{8}{3}

+1

Solution steps

\int_{- 1}^{1} 1 + x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 1 d x + \int_{- 1}^{1} x^{2} d x

\int_{- 1}^{1} 1 d x = 2

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

= 2 + \frac{2}{3}

Simplify

2 + \frac{2}{3} : \frac{8}{3}

= \frac{8}{3}

Popular Examples

integral from 0 to 2 of 2^{5x}

\int_{0}^{2} 2^{5 x} d x

integral from 0 to 3 of (2x+5)

\int_{0}^{3} (2 x + 5) d x

integral from 0 to 1 of cosh^2(x)

\int_{0}^{1} cosh^{2} (x) d x

integral from 1 to 9 of 3sqrt(u)

\int_{1}^{9} 3 u d u

integral from 0 to 0.34 of ln(1+x^2)

\int_{0}^{0.34} ln (1 + x^{2}) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of 1+x^2 ?
The integral from-1 to 1 of 1+x^2 is 8/3