What is the integral from 0 to 1 of 4y^4 ?

The integral from 0 to 1 of 4y^4 is 4/5

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integral from 0 to 1 of 4y^4

\int_{0}^{1} 4 y^{4} d y

\frac{4}{5}

Solution steps

\int_{0}^{1} 4 y^{4} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{1} y^{4} d y

Apply the Power Rule

: [\frac{y ^{5}}{5}]_{0}^{1}

= 4 [\frac{y ^{5}}{5}]_{0}^{1}

Compute the boundaries:

\frac{1}{5}

= 4 \cdot \frac{1}{5}

Simplify

= \frac{4}{5}

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What is the integral from 0 to 1 of 4y^4 ?
The integral from 0 to 1 of 4y^4 is 4/5