What is the integral from 0 to 4 of t^2 ?

The integral from 0 to 4 of t^2 is 64/3

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integral from 0 to 4 of t^2

\int_{0}^{4} t^{2} d t

\frac{64}{3}

Solution steps

\int_{0}^{4} t^{2} d t

Apply the Power Rule

: [\frac{t ^{3}}{3}]_{0}^{4}

= [\frac{t ^{3}}{3}]_{0}^{4}

Compute the boundaries:

\frac{64}{3}

= \frac{64}{3}

\int_{1}^{2} \frac{1}{x ^{2} - 1} d x

\int_{1}^{2} x^{2} - 2 x d x

\int_{2}^{9} (4 x + 10) d x

\int_{- 1}^{1} (\frac{12}{x ^{4}} - 3) d x

\int_{0}^{3} (1 + 6 w^{2} - 10 w^{4}) d w

What is the integral from 0 to 4 of t^2 ?
The integral from 0 to 4 of t^2 is 64/3