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Popular >

integral from-5 to 0 of |x+2|

Solution

\int_{- 5}^{0} ∣ x + 2 ∣ d x

Solution

\frac{13}{2}

+1

Solution steps

\int_{- 5}^{0} ∣ x + 2 ∣ d x

Eliminate Absolutes

= \int_{- 5}^{- 2} - x - 2 d x + \int_{- 2}^{0} x + 2 d x

\int_{- 5}^{- 2} - x - 2 d x = \frac{9}{2}

\int_{- 2}^{0} x + 2 d x = 2

= \frac{9}{2} + 2

Simplify

\frac{9}{2} + 2 : \frac{13}{2}

= \frac{13}{2}

Popular Examples

integral from 0 to 2 of 4^{5x}

\int_{0}^{2} 4^{5 x} d x

integral from 2 to 4 of x^2-7x+10

\int_{2}^{4} x^{2} - 7 x + 10 d x

integral from-2 to 1 of 2-x^2

\int_{- 2}^{1} 2 - x^{2} d x

integral from 3.3 to 8.3 of 12x^2-6x+4/x

\int_{3.3}^{8.3} 12 x^{2} - 6 x + \frac{4}{x} d x

integral from-1 to 0 of 3e^{5t-8}

\int_{- 1}^{0} 3 e^{5 t - 8} d t

Frequently Asked Questions (FAQ)

What is the integral from-5 to 0 of |x+2| ?
The integral from-5 to 0 of |x+2| is 13/2