What is laplacetransform cos(5t)+sin(2t) ?

The answer to laplacetransform cos(5t)+sin(2t) is s/(s^2+25)+2/(s^2+4)

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laplacetransform cos(5t)+sin(2t)

laplace transform

cos (5 t) + sin (2 t)

\frac{s}{s ^{2} + 25} + \frac{2}{s ^{2} + 4}

Solution steps

L {cos (5 t) + sin (2 t)}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {cos (5 t)} + L {sin (2 t)}

L {cos (5 t)} : \frac{s}{s ^{2} + 25}

L {sin (2 t)} : \frac{2}{s ^{2} + 4}

= \frac{s}{s ^{2} + 25} + \frac{2}{s ^{2} + 4}

n = 0 \sum \infty \frac{9}{10 0 ^{n}}

\frac{d y}{d x} = \frac{y}{x} ln (\frac{y}{x})

\frac{\partial ^{2}}{\partial r \partial θ} (r (θ) θ)

\frac{d}{d x} ((x + 1) e^{x})

\int x^{11} sin (x^{12}) d x

What is laplacetransform cos(5t)+sin(2t) ?
The answer to laplacetransform cos(5t)+sin(2t) is s/(s^2+25)+2/(s^2+4)