What is the integral from-2 to 4 of (y+4)/2-(y^2)/4 ?

The integral from-2 to 4 of (y+4)/2-(y^2)/4 is 9

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integral from-2 to 4 of (y+4)/2-(y^2)/4

\int_{- 2}^{4} \frac{y + 4}{2} - \frac{y ^{2}}{4} d y

9

Solution steps

\int_{- 2}^{4} \frac{y + 4}{2} - \frac{y ^{2}}{4} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{4} \frac{y + 4}{2} d y - \int_{- 2}^{4} \frac{y ^{2}}{4} d y

\int_{- 2}^{4} \frac{y + 4}{2} d y = 15

\int_{- 2}^{4} \frac{y ^{2}}{4} d y = 6

= 15 - 6

Simplify

= 9

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What is the integral from-2 to 4 of (y+4)/2-(y^2)/4 ?
The integral from-2 to 4 of (y+4)/2-(y^2)/4 is 9