What is the integral from 3 to 2 of (sqrt(x)) ?

The integral from 3 to 2 of (sqrt(x)) is -2sqrt(3)+(4sqrt(2))/3

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integral from 3 to 2 of (sqrt(x))

\int_{3}^{2} (x) d x

- 23 + \frac{4 2}{3}

Solution steps

\int_{3}^{2} x d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{2}^{3} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{2}^{3}

= - [\frac{2}{3} x^{\frac{3}{2}}]_{2}^{3}

Compute the boundaries:

23 - \frac{4 2}{3}

= - (23 - \frac{4 2}{3})

Simplify

= - 23 + \frac{4 2}{3}

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What is the integral from 3 to 2 of (sqrt(x)) ?
The integral from 3 to 2 of (sqrt(x)) is -2sqrt(3)+(4sqrt(2))/3