What is the integral from z to sqrt(4-z^2 of)z ?

The integral from z to sqrt(4-z^2 of)z is 2-z^2

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integral from z to sqrt(4-z^2 of)z

\int_{z}^{4 - z^{2}} z d z

2 - z^{2}

Solution steps

\int_{z}^{4 - z^{2}} z d z

Apply the Power Rule

: [\frac{z ^{2}}{2}]_{z}^{4 - z^{2}}

= [\frac{z ^{2}}{2}]_{z}^{4 - z^{2}}

Compute the boundaries:

\frac{1}{2} (4 - z^{2}) - \frac{z ^{2}}{2}

= \frac{1}{2} (4 - z^{2}) - \frac{z ^{2}}{2}

Simplify

= 2 - z^{2}

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What is the integral from z to sqrt(4-z^2 of)z ?
The integral from z to sqrt(4-z^2 of)z is 2-z^2