What is the integral from 0 to 4 of (x+4)^3 ?

The integral from 0 to 4 of (x+4)^3 is 960

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integral from 0 to 4 of (x+4)^3

\int_{0}^{4} (x + 4)^{3} d x

960

Solution steps

\int_{0}^{4} (x + 4)^{3} d x

Apply u-substitution

: \int_{4}^{8} u^{3} d u

= \int_{4}^{8} u^{3} d u

Apply the Power Rule

: [\frac{u ^{4}}{4}]_{4}^{8}

= [\frac{u ^{4}}{4}]_{4}^{8}

Compute the boundaries:

960

= 960

\int_{0}^{4} x x + 5 d x

\int_{0}^{1} \frac{x - x}{4} d x

\int_{- 8}^{0} x^{3} d x

\int_{0}^{11} \frac{sin ( x )}{10} + 4 d x

\int_{1}^{2} \frac{1}{1 + x} d x

What is the integral from 0 to 4 of (x+4)^3 ?
The integral from 0 to 4 of (x+4)^3 is 960