What is the integral from 8 to x of 1/t ?

The integral from 8 to x of 1/t is ln|x|-3ln(2)

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integral from 8 to x of 1/t

\int_{8}^{x} \frac{1}{t} d t

ln ∣ x ∣ - 3 ln (2)

Solution steps

\int_{8}^{x} \frac{1}{t} d t

Use the common integral:

\int \frac{1}{t} d t = ln (∣ t ∣)

= [ln ∣ t ∣]_{8}^{x}

Compute the boundaries:

ln ∣ x ∣ - 3 ln (2)

= ln ∣ x ∣ - 3 ln (2)

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\int_{1}^{6} x e^{2 x} d x

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\int_{0}^{x} \frac{1}{( 1 + z ) ^{2}} d z

What is the integral from 8 to x of 1/t ?
The integral from 8 to x of 1/t is ln|x|-3ln(2)