What is the integral from 0 to 1 of 1/(x^q) ?

The integral from 0 to 1 of 1/(x^q) is 1/(-q+1)

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integral from 0 to 1 of 1/(x^q)

\int_{0}^{1} \frac{1}{x ^{q}} d x

\frac{1}{- q + 1}

Solution steps

\int_{0}^{1} \frac{1}{x ^{q}} d x

Apply the Power Rule

: [\frac{x ^{- q + 1}}{- q + 1}]_{0}^{1}

= [\frac{x ^{- q + 1}}{- q + 1}]_{0}^{1}

Compute the boundaries:

\frac{1}{- q + 1}

= \frac{1}{- q + 1}

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What is the integral from 0 to 1 of 1/(x^q) ?
The integral from 0 to 1 of 1/(x^q) is 1/(-q+1)