What is the integral from 0 to x^4 of sec(t) ?

The integral from 0 to x^4 of sec(t) is ln|tan(x^4)+sec(x^4)|

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to x^4 of sec(t)

\int_{0}^{x^{4}} sec (t) d t

ln tan (x^{4}) + sec (x^{4})

Solution steps

\int_{0}^{x^{4}} sec (t) d t

Use the common integral:

\int sec (t) d t = ln ∣ tan (t) + sec (t) ∣

= [ln ∣ tan (t) + sec (t) ∣]_{0}^{x^{4}}

Compute the boundaries:

ln tan (x^{4}) + sec (x^{4})

= ln tan (x^{4}) + sec (x^{4})

\int_{0}^{\frac{1}{2}} e^{x^{2}} d x

\int_{- 2}^{3} (4 x - 3) d x

\int_{0}^{4} (2 x - x) d x

\int_{- 1}^{3} (5 x^{4} + 3 x^{2}) d x

\int_{0}^{8} (x^{2}) d x

What is the integral from 0 to x^4 of sec(t) ?
The integral from 0 to x^4 of sec(t) is ln|tan(x^4)+sec(x^4)|