What is the integral from 0 to 1 of arctan(x ?

The integral from 0 to 1 of arctan(x is arctan(d) 1/2

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integral from 0 to 1 of arctan(x

\int_{0}^{1} arctan (d) x d x

arctan (d) \frac{1}{2}

Solution steps

\int_{0}^{1} arctan (d) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= arctan (d) \cdot \int_{0}^{1} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1}

= arctan (d) [\frac{x ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= arctan (d) \frac{1}{2}

\int_{0}^{1} \frac{5}{1 + p ^{2}} d p

\int_{- 5}^{6} \frac{1}{2} x d x

\int_{0}^{1} 5 z^{4} d z

\int_{3}^{0} 15 w^{4} - 13 w^{2} + w d w

\int_{- 5}^{1} (- x^{2} - 3 x) d x

What is the integral from 0 to 1 of arctan(x ?
The integral from 0 to 1 of arctan(x is arctan(d) 1/2