What is the integral from 0 to pi of (sin(x))/2 ?

The integral from 0 to pi of (sin(x))/2 is 1

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integral from 0 to pi of (sin(x))/2

\int_{0}^{π} \frac{sin ( x )}{2} d x

1

Solution steps

\int_{0}^{π} \frac{sin ( x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= \frac{1}{2} [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= \frac{1}{2} \cdot 2

Simplify

= 1

\int_{2 π}^{3 π} x sin (x) d x

\int_{1}^{0} (e^{x} + e^{- 3}) d x

\int_{0}^{r^{2}} r sin (θ) d z

\int_{\frac{π}{2}}^{π} (x sin (x)) d x

\int_{- 1}^{0} - x^{2} - x d x

What is the integral from 0 to pi of (sin(x))/2 ?
The integral from 0 to pi of (sin(x))/2 is 1