What is the integral from 0 to 2 of (2^x+3) ?

The integral from 0 to 2 of (2^x+3) is 3/(ln(2))+6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of (2^x+3)

\int_{0}^{2} (2^{x} + 3) d x

\frac{3}{ln ( 2 )} + 6

Decimal

10.32808 \dots

Solution steps

\int_{0}^{2} 2^{x} + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 2^{x} d x + \int_{0}^{2} 3 d x

\int_{0}^{2} 2^{x} d x = \frac{3}{ln ( 2 )}

\int_{0}^{2} 3 d x = 6

= \frac{3}{ln ( 2 )} + 6

\int_{- 2}^{5} x^{2} d x

\int_{0}^{1} (8 x^{e} + 3 e^{x}) d x

\int_{0}^{2 π} (sin (x))^{4} d x

\int_{8}^{1} (3 x + 1) d x

\int_{4}^{9} 5 d x

What is the integral from 0 to 2 of (2^x+3) ?
The integral from 0 to 2 of (2^x+3) is 3/(ln(2))+6