integral from 0 to 2pi of cos(t)+sin(t)

Lösung

\int_{0}^{2 π} cos (t) + sin (t) d t

0

Schritte zur Lösung

\int_{0}^{2 π} cos (t) + sin (t) d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2 π} cos (t) d t + \int_{0}^{2 π} sin (t) d t

\int_{0}^{2 π} cos (t) d t = 0

\int_{0}^{2 π} sin (t) d t = 0

= 0 + 0

Vereinfache

= 0

\int_{2}^{3} 1 - \frac{4}{x ^{2}} d x

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