What is the integral from-32 to 32 of \sqrt[5]{x^4} ?

The integral from-32 to 32 of \sqrt[5]{x^4} is 5120/9

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integral from-32 to 32 of \sqrt[5]{x^4}

\frac{5120}{9}

Solution steps

assuming

x \geq 0

= \int_{- 32}^{32} x^{\frac{4}{5}} d x

Apply the Power Rule

: [\frac{5}{9} x^{\frac{9}{5}}]_{- 32}^{32}

= [\frac{5}{9} x^{\frac{9}{5}}]_{- 32}^{32}

Compute the boundaries:

\frac{5120}{9}

= \frac{5120}{9}

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What is the integral from-32 to 32 of \sqrt[5]{x^4} ?
The integral from-32 to 32 of \sqrt[5]{x^4} is 5120/9