What is the integral from 1 to x of x^3 ?

The integral from 1 to x of x^3 is (x^4-1)/4

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integral from 1 to x of x^3

\int_{1}^{x} x^{3} d x

\frac{x ^{4} - 1}{4}

Solution steps

\int_{1}^{x} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{1}^{x}

= [\frac{x ^{4}}{4}]_{1}^{x}

Compute the boundaries:

\frac{x ^{4}}{4} - \frac{1}{4}

= \frac{x ^{4}}{4} - \frac{1}{4}

Simplify

= \frac{x ^{4} - 1}{4}

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What is the integral from 1 to x of x^3 ?
The integral from 1 to x of x^3 is (x^4-1)/4