What is the integral from 0 to 2 of 12x^3 ?

The integral from 0 to 2 of 12x^3 is 48

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of 12x^3

\int_{0}^{2} 12 x^{3} d x

48

Solution steps

\int_{0}^{2} 12 x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 12 \cdot \int_{0}^{2} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{2}

= 12 [\frac{x ^{4}}{4}]_{0}^{2}

Compute the boundaries:

4

= 12 \cdot 4

Simplify

= 48

\int_{1}^{6} 8 x^{3} - 6 x^{- 2} d x

\int_{0}^{1} (1 + x^{2}) d x

\int_{0}^{1} 2 x^{2} - 2 x^{3} d x

\int_{0}^{e x} t (t - π) e^{- t^{2}} d t

\int_{1}^{e} in x d x

What is the integral from 0 to 2 of 12x^3 ?
The integral from 0 to 2 of 12x^3 is 48