What is the integral from 0 to 10 of 1/(1+x) ?

The integral from 0 to 10 of 1/(1+x) is ln(11)

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integral from 0 to 10 of 1/(1+x)

\int_{0}^{10} \frac{1}{1 + x} d x

ln (11)

Decimal Notation

2.39789 \dots

Solution steps

\int_{0}^{10} \frac{1}{1 + x} d x

Apply u-substitution

: \int_{1}^{11} \frac{1}{u} d u

= \int_{1}^{11} \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= [ln ∣ u ∣]_{1}^{11}

Compute the boundaries:

ln (11)

= ln (11)

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What is the integral from 0 to 10 of 1/(1+x) ?
The integral from 0 to 10 of 1/(1+x) is ln(11)