What is the integral from 0 to 4 of-sqrt(x) ?

The integral from 0 to 4 of-sqrt(x) is -16/3

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integral from 0 to 4 of-sqrt(x)

\int_{0}^{4} - x d x

- \frac{16}{3}

Decimal Notation

- 5.33333 \dots

Solution steps

\int_{0}^{4} - x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{4} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{4}

= - [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{4}

Compute the boundaries:

\frac{16}{3}

= - \frac{16}{3}

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What is the integral from 0 to 4 of-sqrt(x) ?
The integral from 0 to 4 of-sqrt(x) is -16/3