What is the sum from n=1 to infinity of ((-3)^n)/(7^{n+1)} ?

The sum from n=1 to infinity of ((-3)^n)/(7^{n+1)} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of ((-3)^n)/(7^{n+1)}

n = 1 \sum \infty \frac{( - 3 ) ^{n}}{7 ^{n + 1}}

converges

Solution steps

n = 1 \sum \infty \frac{( - 3 ) ^{n}}{7 ^{n + 1}}

Apply Series Ratio Test:

converges

= converges

\int 8 (y^{4} + 4 y^{2} + 1)^{2} (y^{3} + 2 y) d y

y^{^{'}} + 3 (1 + x^{2}) y = 0

\frac{d}{d m} (mi)

a e^{v} + \frac{b}{v} + \frac{c}{v ^{2}}

\frac{x}{6 x + 4}

What is the sum from n=1 to infinity of ((-3)^n)/(7^{n+1)} ?
The sum from n=1 to infinity of ((-3)^n)/(7^{n+1)} is converges