What is the integral from 0 to 1 of e^{-x}x ?

The integral from 0 to 1 of e^{-x}x is -2/e+1

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integral from 0 to 1 of e^{-x}x

\int_{0}^{1} e^{- x} x d x

- \frac{2}{e} + 1

Decimal Notation

0.26424 \dots

Solution steps

\int_{0}^{1} e^{- x} x d x

Apply Integration By Parts

: [- e^{- x} x - \int - e^{- x} d x]_{0}^{1}

= [- e^{- x} x - \int - e^{- x} d x]_{0}^{1}

\int - e^{- x} d x = e^{- x}

= [- e^{- x} x - e^{- x}]_{0}^{1}

Compute the boundaries:

- \frac{2}{e} + 1

= - \frac{2}{e} + 1

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What is the integral from 0 to 1 of e^{-x}x ?
The integral from 0 to 1 of e^{-x}x is -2/e+1