What is the integral from 0 to 1 of g(x) ?

The integral from 0 to 1 of g(x) is g/2

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integral from 0 to 1 of g(x)

\int_{0}^{1} g (x) d x

\frac{g}{2}

Solution steps

\int_{0}^{1} gx d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= g \cdot \int_{0}^{1} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1}

= g [\frac{x ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= g \frac{1}{2}

Simplify

= \frac{g}{2}

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What is the integral from 0 to 1 of g(x) ?
The integral from 0 to 1 of g(x) is g/2