What is the integral from 0 to 1 of x^2(x^{2/3}) ?

The integral from 0 to 1 of x^2(x^{2/3}) is 3/11

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integral from 0 to 1 of x^2(x^{2/3})

\int_{0}^{1} x^{2} (x^{\frac{2}{3}}) d x

\frac{3}{11}

Decimal Notation

0.27272 \dots

Solution steps

\int_{0}^{1} x^{2} x^{\frac{2}{3}} d x

Simplify

x^{2} x^{\frac{2}{3}} : x^{\frac{8}{3}}

= \int_{0}^{1} x^{\frac{8}{3}} d x

Apply the Power Rule

: [\frac{3}{11} x^{\frac{11}{3}}]_{0}^{1}

= [\frac{3}{11} x^{\frac{11}{3}}]_{0}^{1}

Compute the boundaries:

\frac{3}{11}

= \frac{3}{11}

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What is the integral from 0 to 1 of x^2(x^{2/3}) ?
The integral from 0 to 1 of x^2(x^{2/3}) is 3/11