What is the integral from 1 to e^3 of 1/t ?

The integral from 1 to e^3 of 1/t is 3

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integral from 1 to e^3 of 1/t

\int_{1}^{e^{3}} \frac{1}{t} d t

3

Solution steps

\int_{1}^{e^{3}} \frac{1}{t} d t

Use the common integral:

\int \frac{1}{t} d t = ln (∣ t ∣)

= [ln ∣ t ∣]_{1}^{e^{3}}

Compute the boundaries:

3

= 3

\int_{- a}^{a} cos^{2} (t) d t

\int_{- 1}^{1} x^{\frac{4}{3}} d x

\int_{0}^{0.5} \frac{1}{x ln ( x )} d x

\int_{0}^{1} 2 e^{r^{2}} r d r

\int_{0}^{15} x^{2} d x

What is the integral from 1 to e^3 of 1/t ?
The integral from 1 to e^3 of 1/t is 3