What is the integral from 0 to x of x/8 ?

The integral from 0 to x of x/8 is (x^2)/(16)

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integral from 0 to x of x/8

\int_{0}^{x} \frac{x}{8} d x

\frac{x ^{2}}{16}

Solution steps

\int_{0}^{x} \frac{x}{8} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int_{0}^{x} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{x}

= \frac{1}{8} [\frac{x ^{2}}{2}]_{0}^{x}

Compute the boundaries:

\frac{x ^{2}}{2}

= \frac{1}{8} \cdot \frac{x ^{2}}{2}

Simplify

= \frac{x ^{2}}{16}

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What is the integral from 0 to x of x/8 ?
The integral from 0 to x of x/8 is (x^2)/(16)