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Popular >

integral from-1 to 1 of x^2+6x+2

Solution

\int_{- 1}^{1} x^{2} + 6 x + 2 d x

Solution

\frac{14}{3}

+1

Decimal

4.66666 \dots

Solution steps

\int_{- 1}^{1} x^{2} + 6 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x^{2} d x + \int_{- 1}^{1} 6 x d x + \int_{- 1}^{1} 2 d x

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

\int_{- 1}^{1} 6 x d x = 0

\int_{- 1}^{1} 2 d x = 4

= \frac{2}{3} + 0 + 4

Simplify

\frac{2}{3} + 0 + 4 : \frac{14}{3}

= \frac{14}{3}

Graph

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\int_{1}^{3} 95 + 972 x^{2} - 18 x d x

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\int_{1}^{0} 2 x + 3 d x

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\int_{0}^{\frac{π}{6}} (5 cos (3 θ))^{2} d θ

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\int_{1}^{3} 4 - x^{2} d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of x^2+6x+2 ?
The integral from-1 to 1 of x^2+6x+2 is 14/3