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Popular >

integral from 1 to 5 of (2x+7)

Solution

\int_{1}^{5} (2 x + 7) d x

Solution

52

Solution steps

\int_{1}^{5} 2 x + 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} 2 x d x + \int_{1}^{5} 7 d x

\int_{1}^{5} 2 x d x = 24

\int_{1}^{5} 7 d x = 28

= 24 + 28

Simplify

= 52

Graph

Popular Examples

integral from 1 to 3 of (3x^2+3)

\int_{1}^{3} (3 x^{2} + 3) d x

integral from y to 3y of (x+y)

\int_{y}^{3 y} (x + y) d x

integral from 0 to 4 of t

\int_{0}^{4} t d t

integral from-1 to 5 of (2x-5)

\int_{- 1}^{5} (2 x - 5) d x

integral from 1 to 4 of 3/(1-2x)

\int_{1}^{4} \frac{3}{1 - 2 x} d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 5 of (2x+7) ?
The integral from 1 to 5 of (2x+7) is 52